Math

How to Find a Missing Number from an Average

Learn how to find a missing value when the average and the other numbers are known by calculating the required total.

Updated July 15, 2026

To find a missing number from a known average, multiply the average by the total number of values to find the required sum. Add the known values, then subtract their total from the required sum. The difference is the missing number.

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The known average and number of values reveal what the complete sum must be.

Finding a missing number from an average An average of 20 across four values requires a total of 80. Known values total 50, so the missing value is 30.20 × 4Required total: 8010 + 15 + 25Known total: 5080 − 50Missing value: 30Missing number = Required total − Known total

The Reverse Average Method

An arithmetic mean is normally found by dividing a total by a count.

When the average is already known, reverse the division by multiplying the average by the count.

The Average Calculator can verify the result after the missing value has been found.

Missing-Number Formula

Multiply the known average by the total number of values.

Add all known values.

Subtract the known total from the required total.

Missing-value formulaMissing value = Average × Total count − Sum of known values

Worked Example

Suppose four numbers have an average of 20, and three known values are 10, 15, and 25.

The required total is 20 multiplied by four, which equals 80.

The known values total 50, so the missing number is 80 minus 50, or 30.

Required total80
Known total50
Missing value30

Verify the Missing Value

Add the recovered value to the known values.

The complete set is 10, 15, 25, and 30, which totals 80.

Dividing 80 by four confirms the average of 20.

Example with a Decimal Average

Suppose five values average 7.5 and four known values total 29.

The required total is 7.5 multiplied by five, which equals 37.5.

The missing value is 37.5 minus 29, or 8.5.

Example with a Negative Missing Value

Suppose three values average two and two known values are five and four.

The required total is six, while the known total is nine.

The missing value is six minus nine, which equals minus three.

Finding Multiple Missing Values

When more than one value is missing, the average reveals only their combined total.

Additional information is needed to identify each missing value separately.

For example, knowing their difference or ratio may make the individual values solvable.

Finding a Required Future Score

The same method can determine the score needed to reach a target average.

Multiply the target average by the final number of scores and subtract the current total.

The result is the required next score, assuming all scores are equally weighted.

Weighted Missing Values

The simple reverse method assumes equal weighting.

When the missing value has a different weight, calculate the required weighted total and divide the remaining contribution by the missing weight.

Read How to Calculate a Weighted Average first.

Common Mistakes

Do not multiply by the number of known values; use the total count including the missing value.

Do not subtract individual known numbers from the average itself.

Do not apply the equal-weight formula to weighted observations.

Conclusion

Find the required total by multiplying the average by the total count.

Subtract the sum of the known values to recover the missing number.

Enter the completed list into the Average Calculator to verify the result.

FAQs

How do I find a missing number from an average?

Multiply the average by the total count and subtract the sum of the known values.

Does the count include the missing value?

Yes. Use the total number of values after the missing value is included.

Can the missing value be negative?

Yes. It can be negative when the known total exceeds the required total.

Can I find two missing values?

You can find their combined total, but more information is needed to identify them separately.

How do I verify the result?

Add the missing value to the list and calculate the average again.

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